(ii) an = (−1)n+1 n(n + 1)
Solution :
an = (−1)n+1 n(n + 1)
n = 1
= (−1)n+1 n(n + 1)
= (−1)1+1 1(1 + 1)
= 1 (2)
a1 = 2
|
n = 2
= (−1)n+1 n(n + 1)
= (−1)2+1 2(2 + 1)
= -1 (6)
a2 = -6
|
n = 3
= (−1)n+1 n(n + 1)
= (−1)3+1 3(3 + 1)
= 1 (12)
a3 = 12
|
n = 4
= (−1)n+1 n(n + 1)
= (−1)4+1 4(4 + 1)
= -1 (20)
a4 = -20
|
Hence the first four terms are 2, -6, 12, -20.